nightmare3519 Posted September 14, 2013 Share Posted September 14, 2013 (edited) Edited September 2, 2014 by nightmare3519 Quote Link to comment Share on other sites More sharing options...
KintaRo Posted September 14, 2013 Share Posted September 14, 2013 WaitForReturn false olduğu için olmuyor, yani menü çalışıp işi bitiyor, geri dönüş beklemiyor, true yapınca düzelecektir. Quote Link to comment Share on other sites More sharing options...
superhalit Posted September 15, 2013 Share Posted September 15, 2013 tblMenu={} tblMenu[1] = {} tblMenu[1].Text = "Programı Değiştir" tblMenu[1].ID = 200 tblMenu[1].IconID = 0; tblMenu[1].Checked = false; tblMenu[1].Enabled = true; ptMouse = System.GetMousePosition(true, nil); nRes = Application.ShowPopupMenu(ptMouse.X, ptMouse.Y, tblMenu, TPM_LEFTALIGN, TPM_TOPALIGN, true, true); if (nRes == 200) then Dialog.Message("","Deneme") end Quote Link to comment Share on other sites More sharing options...
Ankara1703 Posted September 16, 2013 Share Posted September 16, 2013 KintaRO doğru Söylüyor döngü lazım Quote Link to comment Share on other sites More sharing options...
KintaRo Posted September 16, 2013 Share Posted September 16, 2013 hayır döngü değil dönüş lazım. loop ayrı şey, return ayrı şey. mesaj yazmış olmak için mesaj yazmayın lütfen. Quote Link to comment Share on other sites More sharing options...
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